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## Study the De Morgans theorems and their working using logic circuitsPosted by: seminar class Created at: Friday 13th of May 2011 05:27:12 AM Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM | wiring diagram 7404 7408 7432 ,
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t LHS & RHS of given equation are equal. LHS = Let A = B = 0; then = = = 1 Let A = 0 & B = 1; then = = = 1 Let A = 1 & B = 0; then = = = 1 Let A = B = 1; then = = = 0 RHS = Let A = B = 0; then = = 1 + 1 = 1 Let A = 0 & B = 1; then = = 1+ 0 = 1 Let A = 1 & B = 0; then = = 0 + 1 = 1 Let A = B = 1; then = = 0 + 0 = 0 Thus, LHS = RHS, hence proved. Second theorem – it states that the complement of sum is equal to the product of the
complements. Logic equation Proof – we shall prove the theorem by showing that LHS & RH.................. [:=> Show Contents <=:] | |||

## Study the De Morgans theorems and their working using logic circuitsPosted by: seminar class Created at: Friday 13th of May 2011 05:27:12 AM Last Edited Or Replied at :Friday 13th of May 2011 05:27:12 AM | wiring diagram 7404 7408 7432 ,
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Let A = B = 1; then = = = 0 RHS = Let A = B = 0; then = = 1.1 = 1 Let A = 0 & B = 1; then = = 1.0 = 0 Let A = 1 & B = 0; then = = 0.1 = 0 Let A = B = 1; then.................. [:=> Show Contents <=:] |

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